Chorula
Chorulla | |
|---|---|
Village | |
 Church | |
  Chorula | |
| Coordinates: 50°32′N 17°58′E / 50.533°N 17.967°E | |
| Country |  Poland |
| Voivodeship | Opole |
| County | Krapkowice |
| Gmina | Gogolin |
| Population | 640 |
| Website | http://www.chorula.pl/ |
Chorula [xɔˈrula], additional name in German: Chorulla,[1] is a village in the administrative district of Gmina Gogolin, within Krapkowice County, Opole Voivodeship, in south-western Poland.[2] It lies approximately 7 km (4 mi) north-west of Gogolin, 8 km (5 mi) north of Krapkowice, and 15 km (9 mi) south of the regional capital Opole.
References
[edit]- ^ Państwowy Rejestr Nazw Geograficznych – miejscowości – format XLSX, Place Names Register of Poland – PRNG, Head Office of Geodesy and Cartography, 24 August 2025, PRNG identifier: 16288
- ^ "Główny Urząd Statystyczny" [Central Statistical Office] (in Polish). To search: Select "Miejscowości (SIMC)" tab, select "fragment (min. 3 znaki)" (minimum 3 characters), enter town name in the field below, click "WYSZUKAJ" (Search).
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